Construct a triangle abc in which bc=5cm angle b=45 degree ab- ac=2.8cm Justify your construction
Dear Student,
Please find below the solution to the asked query:
We follow these steps to form our triangle ABC : given angle is = 45 , BC = 5 cm and AB - AC = 2.8 cm
Step 1 : Draw a line BC = 5 cm
Step 2 :Take any radius ( Less than half of BC ) and center " B " we draw a semicircle that intersect our line BC at "P " . With same radius take center " P " draw an arc that intersect our semicircle at " Q " And with same radius take center " Q " draw an arc that intersect our semicircle at " R " .
Step 3 : With same radius take center " Q " and " R " draw two arcs that intersect each other at " S " . Join line BS , that intersect our semicircle at " T "
Step 4 : With same radius take center " P " and " T " draw two arcs that intersect each other at " U " . Join BU . and extend it to V , we get VBC =45
Step 5 : Take radius of 2.8 cm and center " B " draw an arc that intersect our line BV at " W " . Join CW
Step 6 : Now take radius more than half of CW and cneter " C " and " W " draw two arc from both points on both side of line CW, and these arcs intersect at " X " and " Y " .
Step 7 : Join line XY and that intersect line BV at " A " .
This is our required triangle ABC .
![](https://s3mn.mnimgs.com/img/shared/ck-files/ck_566e3c01ae6b6.jpg)
Hope this information will clear your doubts about Construction .
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
We follow these steps to form our triangle ABC : given angle is = 45 , BC = 5 cm and AB - AC = 2.8 cm
Step 1 : Draw a line BC = 5 cm
Step 2 :Take any radius ( Less than half of BC ) and center " B " we draw a semicircle that intersect our line BC at "P " . With same radius take center " P " draw an arc that intersect our semicircle at " Q " And with same radius take center " Q " draw an arc that intersect our semicircle at " R " .
Step 3 : With same radius take center " Q " and " R " draw two arcs that intersect each other at " S " . Join line BS , that intersect our semicircle at " T "
Step 4 : With same radius take center " P " and " T " draw two arcs that intersect each other at " U " . Join BU . and extend it to V , we get VBC =45
Step 5 : Take radius of 2.8 cm and center " B " draw an arc that intersect our line BV at " W " . Join CW
Step 6 : Now take radius more than half of CW and cneter " C " and " W " draw two arc from both points on both side of line CW, and these arcs intersect at " X " and " Y " .
Step 7 : Join line XY and that intersect line BV at " A " .
This is our required triangle ABC .
![](https://s3mn.mnimgs.com/img/shared/ck-files/ck_566e3c01ae6b6.jpg)
Hope this information will clear your doubts about Construction .
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards