check your question..it must be atomisation of H2 bond(=52.1 kcal)
see..you knw that..,
(delta)fH=(heat of atomisation of C)*2+(heat of atomisation of H)*4-(bond energy of C-H)*4-(bond energy of C=C)
as C has 2 moles
H has 4 moles
and C2H4 has 4 C-H bonds..
thus if u replace the values..and calculate..you are getting the value as..
(bond energy of C=C)=140.9 kcal
answer is thus (1)..
check your question..still..hope my answer helps you..^_^