Dear Student , Please find below the solution to the asked query : Amount won by person be:-Rs 1 , when die shows 1 + Rs 2 , when die shows 2 -Rs 3 , when die shows 3 + Rs 4 , when die shows 4 -Rs 5 , when die shows 5 + Rs 6 , when die shows 6 Let X denotes the amount won by person Values of X =-5 , -3 , -1 , 2 , 4 , 6 P 1 appearing on die=16P 2 appearing on die=16P 3 appearing on die=16P 4 appearing on die=16P 5 appearing on die=16P 6 appearing on die=16 X -5 -3 -1 2 4 6 P (X) 16 16 16 16 16 16 Money he can expect per game =E X=∑ X PX=-516+-316+-116+216+416+616=-5-3-1+2+4+66=36=0 5 ANS He can expext Rs 0 5 per game in the long run Hope this information will clear your doubts about the topic If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible Regards

No links please

No links please If a person gains or, loses an amount equal to the number appearing when a balanced die is rolled once, according to whether the number is even or odd, how much money can he expect per game in the long run? A two unbiased dice and stands to loss 2 if he

Dear Student ,

Please find below the solution to the asked query :

Amount won by person be : - Rs . 1, when die shows 1 . + Rs . 2, when die shows 2 . - Rs . 3, when die shows 3 . + Rs . 4, when die shows 4 . - Rs . 5, when die shows 5 . + Rs . 6, when die shows 6 . Let X denotes the amount won by person . Values of X = \{- 5, - 3, - 1, 2, 4, 6\} P (1 appearing on die) = \frac{1}{6} P (2 appearing on die) = \frac{1}{6} P (3 appearing on die) = \frac{1}{6} P (4 appearing on die) = \frac{1}{6} P (5 appearing on die) = \frac{1}{6} P (6 appearing on die) = \frac{1}{6}

X	-5	-3	-1	2	4	6
P (X)	$\frac{1}{6}$	$\frac{1}{6}$	$\frac{1}{6}$	$\frac{1}{6}$	$\frac{1}{6}$	$\frac{1}{6}$

Money he can expect per game = E (X) = \sum_{}^{} X . P (X) = - 5 (\frac{1}{6}) + (- 3) (\frac{1}{6}) + (- 1) (\frac{1}{6}) + 2 (\frac{1}{6}) + 4 (\frac{1}{6}) + 6 (\frac{1}{6}) = \frac{- 5 - 3 - 1 + 2 + 4 + 6}{6} = \frac{3}{6} = 0.5 ANS . . . He can expext Rs 0.5 per game in the long run .

Hope this information will clear your doubts about the topic .

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible .

Regards

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No links please No links please If a person gains or, loses an amount equal to the number appearing when a balanced die is rolled once, according to whether the number is even or odd, how much money can he expect per game in the long run? A two unbiased dice and stands to loss 2 if he

No links please

No links please If a person gains or, loses an amount equal to the number appearing when a balanced die is rolled once, according to whether the number is even or odd, how much money can he expect per game in the long run? A two unbiased dice and stands to loss 2 if he