Pls solve the no 3 sum plsss. Pls solve the no 3 sum plsss. 0 00 00 0 Share with your friends Share 0 Yasodharan answered this Dear Student, The computation are expressed below, ∆H=∆U+p∆V⇒∆H=∆U+nRT = -332 kJ +(1×0.00831×298) = -332 kJ + 2.477 kJ = -329.52 kJ Regards. 0 View Full Answer
