Plse ans Plse ans A a and an 0 m c to the of at fed pctpcti'lftMlat field With k tncttc of' the tildii 01 the circular cnet "v I hc A nu•tgnctjc 10 Am: dipole and of nvtgneuc of rmnrnt Inertia Share with your friends Share 0 Tanoj Sharma answered this radius=((2mK)1/2)/qB because mv=(2mK)1/2 where k=kinetic energy so by putting value u can easily find the answer 1 View Full Answer V A R C H A S V A answered this Kavya, ek kavita sunao na 1
