Plz answer quickly. Qno. 8

Plz answer quickly. Qno. 8 (B) 4A 8. lov In the circuit shown, 30 lov 50 30 20 60 (A) The equivalent resistance between the points A and B is 5 Q (B) The current in the 5 Q resistor is 2/3 A. (C) The potential difference across the 6 Q resistor is 1/6 V (D) The current coming out of the battery is 2A.

Dear student,
Equivalent resistance

Starting from right side1R=16+161R=1+16, R= 3Again 3 and 3 ohm are in series so R' = 3 + 3 = 6 ohmNow 6 ohm and 3 are in parallel so1R''=16+131R''=1+26, R=22 ohm and 2 ohm are parallel1R'''=12+121R'''=1+12, R=11ohm and 5 ohm are in series so R'''' = 6 ohmNow 3 ohm and 6 are in parallel so1R'''''=13+161R'''''=2+16, R'''''=24 ohm , 4 ohm and 2 ohm are in series Req = 4 + 4+ 2 = 10 ohmCurrent in circuit I = V/Req = 10 V/10 ohm = 1 A
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