Plz explain and answer Q5

Plz explain and answer Q5 j 4 and and 1092 6. of carbon monoxide is maximum at atmand 273 K The acid strength of active methylene group in CH3COCH2COOC2H5 (b) CH3COCH2COCH3 (cy_- C2HsOOCCHqCOOC%Hk dec,eases as _ _-_Oy_aa > b s (2)

Dear Student,

The solution to your query is given as follows:

A c c o r d i n g t o i d e a l g a s e q u a t i o n, P V = n R T, P = P r e s s u r e, V = V o l u m e, n = n u m b e r o f m o l e s, R = G a s c o n s \tan t, T = t e m p e r a t u r e N o w, n u m b e r o f m o l e s = \frac{G i v e n m a s s}{M o l a r m a s s} n = \frac{w}{M} S o, P V = \frac{w}{M} R T S o, \frac{P M}{R T} = \frac{w}{V} = d, \sin c e d e n s i t y i s w e i g h t o v e r v o l u m e S o, d e n s i t y i s d i r e c t l y p r o p o r t i o n a l t o p r e s s u r e b u t i n v e r s e l y p r o p o r t i o n a l t o t h e t e m p e r a t u r e . d \propto \frac{P}{T} C a l c u l a t i n g t h e r a t i o s f o r t h e g i v e n o p t i o n s, \frac{P}{T} f o r o p t i o n 1 = 0.001, f o r o p t i o n 2 = 0.008, f o r o p t i o n 3 = 0.0033 . f o r o p t i o n 4 = 0.0054

Since P/T is highest for option 2, it is the correct answer.

The density of carbon monoxide is maximum at 4 atm and 500 K.

Hope it helps.

Regards