Q 2 mole of zinc is dissolved in HCI at 25 C Calculate the work done in - Chemistry - Thermodynamics

Question

Q 2 mole of zinc is dissolved in HCI at 25 ° C Calculate the
work done in open vessel

Vartika Jain · Accepted Answer

Dear Student,

Zn + HCl → ZnCl2(aq) + H2(g)1 mol                                      1 molSo, 2 mol of Zn = 2 mol of H2In open vessel, gas expands against theexternal pressure of atmosphereSo, w= -pextVVolume occupied by 2 mol of H2 at 1 atm and 25°C i
e  298 KV= nRTP=2×0 082×2981=48
872 LSo, w= -1 atm×48
872 L          =-48
872 L-atm          =-48
872×101
3 J          =-4950
733 J          =-4
95 kJ

Q. 2 mole of zinc is dissolved in HCI at 25 ° C .Calculate the work done in open vessel.

Q. 2 mole of zinc is dissolved in HCI at 25 $°$ C .Calculate the work done in open vessel.