​Q10,11,13

Dear Student,

Kindly ask different questions in different thread. Also, refer the solution of 10th question.

$$\begin{gathered} {\mathrm{T}}^2 \mathrm{\alpha } {\mathrm{a}}^3 \\ \frac{{{\mathrm{T}}_1}^2}{{{\mathrm{a}}_1}^3}=\frac{{{\mathrm{T}}_2}^2}{{{\mathrm{a}}_2}^3} \\ {{\mathrm{T}}_2}^2={\left(\frac{{\mathrm{a}}_2}{{\mathrm{a}}_1}\right)}^3\times {{\mathrm{T}}_1}^2 \\ \mathrm{Now}, \\ {\mathrm{a}}_2=120\% \mathrm{of} {\mathrm{a}}_1 \\ {\mathrm{a}}_2=\frac{120}{100}\times {\mathrm{a}}_1 \\ \frac{{\mathrm{a}}_2}{{\mathrm{a}}_1}=\frac{6}{5} \\ {{\mathrm{T}}_2}^2={\left(\frac{6}{5}\right)}^3\times {{\mathrm{T}}_1}^2 \\ {{\mathrm{T}}_2}^2=\frac{216}{125}\times {{\mathrm{T}}_1}^2 \\ {\mathrm{T}}_2=\sqrt{\frac{216}{125}}\times {\mathrm{T}}_1 \\ {\mathrm{T}}_2=1.31\times 365 \mathrm{days} \\ {\mathrm{T}}_2=478.15 \mathrm{days} \end{gathered}$$