Hi, x = ab2aba2-b2xab=ab2aba2-b2×ab= ab2a2a2-b2xba=ab2aba2-b2×ba= ab2b2a2-b2 now aba2+b2xab+xba=aba2+b2× ab2a2a2-b2+ab2b2a2-b2 Regards

Solve this:

Hi,

x = {(\frac{a}{b})}^{\frac{2 ab}{a^{2} - b^{2}}} x^{\frac{a}{b}} = {(\frac{a}{b})}^{\frac{2 ab}{a^{2} - b^{2}} \times \frac{a}{b}} = {(\frac{a}{b})}^{\frac{2 a^{2}}{a^{2} - b^{2}}} x^{\frac{b}{a}} = {(\frac{a}{b})}^{\frac{2 ab}{a^{2} - b^{2}} \times \frac{b}{a}} = {(\frac{a}{b})}^{\frac{2 b^{2}}{a^{2} - b^{2}}} now \frac{ab}{a^{2} + b^{2}} (x^{\frac{a}{b}} + x^{\frac{b}{a}}) = \frac{ab}{a^{2} + b^{2}} \times [{(\frac{a}{b})}^{\frac{2 a^{2}}{a^{2} - b^{2}}} + {(\frac{a}{b})}^{\frac{2 b^{2}}{a^{2} - b^{2}}}]

Regards