Solve using QUADRATIC equations formula...10x^2+ 3bx +a^2- 7ax - b^2=0..please solve with clear steps...ty

Dear student,

To solve: 10x2+3bx+a2-7ax-b2=010x2+3b-7ax+a2-b2=0using quadratic formulax=-b±b2-4ac2ax=-3b-7a±3b-7a2-4×10×a2-b22×10=-3b-7a±9b2+49a2-42ab-40a2+40b220=-3b-7a±49b2+9a2-42ab20=-3b-7a±7b-3a220=-3b-7a±7b-3a20x=-3b+7a+7b-3a20  and x=-3b+7a-7b+3a20 x=4a+4b20  and x=-10b+10a20 x=(a-b)2    or     x=(a+b)5

Regards

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