The dimensions of a tank are 4m x 3m x 2m. When it is half full , it contains 12000 L of water. If 600 L water is added to the tank, how high will the water level rise ?

Given, dimensions of a tank are  4 m × 3 m × 2 m.

Therefore, volume of the tank = 4 m × 3 m × 2 m = 24 m3 = 24000 L  [As 1 m3 = 1000 L]

Now, it is given that when tank is half filled it contains 12000 L of water.

From above conditions we have, when the tank is completely filled i.e., have an water upto height of 2 m then it contains total 24000 L of water.

So, height of water level when the tank is half-filled = 2/2 m = 1 m

Now, 600 L of water is added to the tank.

Therefore, total amount of water in the tank = 12000 L + 600 L = 12600 L = 12.6 m3  

Let the height of water level = h m

According to the given conditions,

 4 m × 3 m × h m = 12.6

h = 1.05 m

So, increase in water level on adding 600 L of water  = 1.05 m - 1m = 0.05 m  

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Capacity of tank when half full= 12000 L = 12 m3

Height of water when half full = (2/2) m =1 m

Volume of water after additional input of water= ( 12000 + 600) L = 18000 L =18 m3

New hight of water = x

4 X 3 X x = 18

=> x = 1.5 m

 Rise in water level = (1.5 - 1) m =0.5 m

ANSWER= The water level will rise by 0.5 m.

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