1) Draw the graph of the linear equation y = 3x
2) Draw the graph of the linear equation 2x - 3y + 11 = 0 in two variables.
3) If poin ( -2 , 4 ) lies on the graph of the equation y = mx + 5 , then find the value of m .
4) Give the equations of two lines passing through ( 2 , 14 ) . How many more such lines are there , and why ?
5) Draw the graph of 2x + 5y = 12 . Find graphically the values of a) y when x = 1 and b) x when y = 4
(1) The given equation is y = 3x
| x | 1 | 0 | –1 |
| y | 3 | 0 | –3 |
The graph of this equation can be drawn as follows:
(2) Given equation is y = mx + 5
Point (–2, 4) satisfies this equation, so putting x = –2 and y = 4 in the given equation, we get
4 = –2m + 5
⇒ m = 
(3) Equation of lines passing through the point (2, 14) are:
x + y =16, –x + 2y = 26 etc..
Infinite number of lines pass through a given point. This is because for a unique equation of line, we must have 2 conditions. When only 1 condition is given, we can have infinite number of lines.