14 In an ac circuit, emf, E=Eο cosωt and current, I = Iο cos (ωt-θ) Show that, power dissipation - Physics - Alternating Current

Question

14 I n   a n   a c   c i r c u i t ,   e m f ,
  E = E ο   cos ω t   a n d   c u r r
e n t ,   I   =   I ο   cos   (
ω t - θ )   S h o w   t h a t ,   p o w e
r   d i s s i p a t i o n   i n   t h e   c i r
c u i t =   1 2 E ο I o cos θ

Pintu B. · Accepted Answer

Dear Student ,
Power dissipation in an ac circuit is ,

P=EI=E0I0cosωtcosωt-θ=12E0I0×2cos2θ2-1=12E0I0cosθ
Regards

14 . I n a n a c c i r c u i t , e m f , E = E ο cos ω t a n d c u r r e n t , I = I ο cos ( ω t - θ ) . S h o w t h a t , p o w e r d i s s i p a t i o n i n t h e c i r c u i t = 1 2 E ο I o cos θ .

$14 . I n a n a c c i r c u i t, e m f, E = E ο \cos ω t a n d c u r r e n t, I = I ο \cos (ω t - θ) . S h o w t h a t, p o w e r d i s s i p a t i o n i n t h e c i r c u i t = \frac{1}{2} E ο I o \cos θ .$