44) The period of revolution of a satellite orbiting Earth at a height 4R above the surface of Earth is x hrs. where R is the radius of earth. The period of another satellite at a height 1.5 R from the surface of the Earth is. ( 1 ) x 2 2 h r s ( 2 ) x 2 h r s ( 3 ) 2 x h r s ( 4 ) x 2 h r s Share with your friends Share 5 Shobhit Mittal answered this Dear Student , GMm25R2=mv25Rv=GM5Rx=2π5RGM5Rfor 1.5RGMm2.52R2=mv22.5Rv=GM2.5RT=2π2.5RGM2.5RTx=2π2.5RGM2.5R2π5RGM5R=2.5RGM2.5R5RGM5R=122T=x22 hrsRegards -4 View Full Answer