​​5. The length of a rectangle is 8 metres less than twice its breadth. If the perimeter of the rectangle is 56metre, find its length and breadth.
6. A number is divided into two parts such that one part is 10 more than the other. If the two parts are in the ratio 5:3. Find the number and the two parts.

Dear student,
Here is the solution of your asked query:
5.) Let breadth be x.Twice the breadth=2x8m less than twice the breadth=2x-8so, length of rectangle=2x-8And we know that perimeter of rectangle = 2length+breadth so we have;perimeter=2x+2x-8=56 meter2x+22x-8=562x+4x-16=566x=72x=726=12So breadth is 12m.And length =2×12-8=16m                                                    6.) Since two parts are in the ratio 5:3, so let the parts be 5x and 3x.Now according to question we have;one part is 10 more than other;5x=3x+105x-3x=102x=10x=102=5so the parts are 5×5 i.e. 25 and 3×5 i.e. 15.Therefore parts of number are 25 and 15. and the number is 25+15=40                      
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