a battery of emf 3 volts and internal resistance r is connected in series with a resistor of 55 ohm through an ammeter of resistance 1 ohm the ammeter reads 50 miliampere draw circuit and calculate value of r. Share with your friends Share 0 Vipra Mishra answered this Solution The circuit diagram is shown in figure ε = 3VI = 50 mA = 50 ×10-3 ATotal resistance of the circuitR' =55 +1+r = 56 +rAsI =εR' 50 ×10-3 A =3 56 +r 56 +r =3 50 ×10-3 =60r = 4 Ohm 0 View Full Answer