A car starting from rest gets uniformly accelerated & acquires a velocity of 108 km/h in 10 seconds. The average velocity of the car is (A) 15 m/s (B) 72 km/h (C) 10 m/s (D) 50 km/h Share with your friends Share 0 Vipra Mishra answered this Dear Student V = 108 km/hr = 30 m/s Acceleration a = v-ut=30m/s -010=3m/s2 Total distance covereds = ut +12at2=12×3×10×10=150 mSo average velocity = Total displacementtotal time taken=15010=15m/s Regards 2 View Full Answer Will Tenision answered this Here, u = 0 km/h v = 108 km/h t = 10 s average velocity = v+u/t Use this to find your solution Your self! -1
