A cistern, internally measuring 150cm X 120cm X 110cmhas 129600cu. cm of water in it. Porous bricks are placed in the water until the cistern is full to the brim. Each brick absorbs one seventeenth of its own volume of water. How many bricks can be put in it without the water overflowing, each brick being 22.5cm X 7.5cm X 6.5cm?

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 Vol of cistern = 1980000 cm³

vol of brick = 1096.875cm³

Net increase in vol when one brick is put inside cistern

= Vol of brick - vol of water absorbed by brick 

= 1096.875  - 1/17 * 1096.875

= 16/17 * 1096.875 cm³

let n be the no of bricks (n) which can be put in without causing water overflow.

n * 16/17 * 1096.875 = 1980000 - 129600

n= 1850400 *17/(16*1096.875)

n= 1792.410 

Therefore, no. of bricks are 1792 !!

hope this will help u

 Vol of cistern =(150cm * 120cm * 110cm) =1980000 cm ³

vol of brick = (22.5cm * 7.5cm * 6.5cm)= 1096.875cm ³

Net increase in vol when one brick is put inside cistern

= Vol of brick - vol of water absorbed by brick

= 1096.875 - 1/17 * 1096.875

= 16/17 * 1096.875 cm³

let n be the no of bricks (n) which can be put in without causing water overflow.

n * 16/17 * 1096.875 = 1980000 - 129600

n= 1850400 *17/(16*1096.875)

n= 1792.410

Therefore, no. of bricks are 1792 !!

hope this will help u

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