A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s­₁ in the first 10 seconds and distance s₂ in the next 10 seconds then,

A)s₂ =s₁

B)s₂ =2s₁

C)s₂ =3s₁

D)s₂ =4s₁

_{explain ??}

 SRRY ITS NT 4 ITS 2

 s=ut+12a(t^2)

u=0 m/sec          (body starts from rest)

s1=1/2a(t^2)

s1=1/2a(10^2)

s1=50a ------------------(1)

now initial velocity for s2 is the final velocity of s1

let final velocity of s1=initial velocity of s2=v

so, v=u +at

  v=at

  v=10a  (since u=0 and t=10)

now s2=ut+1/2a(t^2)

s2=(10a)10+1/2a(10^2)

s2=100a+50a

s2=150a -------------------------(2)

now

(2)/(1)=s1/s2

S1/s2=50a/150a

3s1=s2

  s=ut+12a(t^2)

u=0 m/sec          (body starts from rest)

s1=1/2a(t^2)

s1=1/2a(10^2)

s1=50a ------------------(1)

now initial velocity for s2 is the final velocity of s1

let final velocity of s1=initial velocity of s2=v

so, v=u +at

  v=at

  v=10a  (since u=0 and t=10)

now s2=ut+1/2a(t^2)

s2=(10a)10+1/2a(10^2)

s2=100a+50a

s2=150a -------------------------(2)

now

(2)/(1)=s1/s2

S1/s2=50a/150a

3s1=s2