A particle is projected from horizontal surface with speed 2/7 m/s at an angle of 60o with horizontal Angular - Physics - Rest and Motion Kinematics

Question

A particle is projected from horizontal surface with speed 2/7 m/s
at an angle of 60o with horizontal Angular speed of the
particle at its highest point with respect to point of projection
is?

Pintu B. · Accepted Answer

Dear Student ,

At the highest point the horizontal velocity of the particle
= vx 
= v cos600 
and the vertical velocity at the highest point is
zero

Now time taken by the particle to reach highest point is t then
,

0=vsin60°-gt⇒t=vsin60°gNow if the maximum height is h then ,h=vsin60°t-12gt2=vsin60°vsin60°g-12gvsin60°g2=v2sin260°g-12v2sin260°g=12v2sin260°g=4×349×2×10×4=3980mSo the angular speed at the highest point is ,ω=vh=27×9803=93·33 rad/s

Hope this helps you

Regards

A particle is projected from horizontal surface with speed 2/7 m/s at an angle of 60o with horizontal. Angular speed of the particle at its highest point with respect to point of projection is?

A particle is projected from horizontal surface with speed 2/7 m/s at an angle of 60^o with horizontal. Angular speed of the particle at its highest point with respect to point of projection is?