A particle is projected from horizontal surface with speed 2/7 m/s at an angle of 60o with horizontal. Angular speed of the particle at its highest point with respect to point of projection is?
Dear Student ,
At the highest point the horizontal velocity of the particle = vx = v cos600 and the vertical velocity at the highest point is zero .
Now time taken by the particle to reach highest point is t then ,
Hope this helps you .
Regards
At the highest point the horizontal velocity of the particle = vx = v cos600 and the vertical velocity at the highest point is zero .
Now time taken by the particle to reach highest point is t then ,
Hope this helps you .
Regards