A soap bubble is blown to a diameter of 7 cm. If 36960 erg of work is done in blowing it further, find the new radius. The surface tension of soap solution is 40 dyne/cm.

Dear student,Work done in blowing a soap bubble =T×8π(R2final-R2initial)RFINAL=?Rinitial=3.5cmT=40dyne/cmWork done=36960ergPutting these values in formula we  get,36960=40×8π(R2final-(3.5)2)R2final=36.78-12.25Rfinal=4.95cmRegards

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