A solid sphere of mass 2kg rolls ona smooth horizontal surface at 10m/s.It then rolls up aon a smooth inclined plane of inclination 30 degree with the horizontal.Find the height attained by the sphere before it stops.
Mechanical energy is conserved.
u=initial velocity
v=final velocity=0 (for max height)
h=initial height=0
d=final height
m=mass
g=10m/s^2
(1/2)mu^2 + mgh = (1/2)mv^2 + mgd
Dividing by m on both sides and substituting values,
=>(1/2)10^2 + 10*0 = (1/2)0^2 +10*d
=>10*d=100/2
=>d=10/2=5 meters
u=initial velocity
v=final velocity=0 (for max height)
h=initial height=0
d=final height
m=mass
g=10m/s^2
(1/2)mu^2 + mgh = (1/2)mv^2 + mgd
Dividing by m on both sides and substituting values,
=>(1/2)10^2 + 10*0 = (1/2)0^2 +10*d
=>10*d=100/2
=>d=10/2=5 meters