A tank is filled with a liquid upto a height H. a small hole is made at the bottom of this tank. let t1 be the time taken to empty first half of the tank and t2 the time taken to empty rest half of the tank. find t1 / t2 Share with your friends Share 5 Sanjay Singh answered this Dear student Formula for the time taken by the liquid to fall its level from h1 to h2 ist=Aa×2g×(h1-h2) (where A is the area of cross section of the cylindrical cross section and a is the area of the orifice)t=c×(h1-h2)h1 is the initial height and h2 is the final heightso we can see from above equation that time is proportional to (h1-h2)so time taken to fall to half the full height ist1=c×(h-h2)=c×h(1-12)=c×h(2-12)...1 time taken to fall from half the full height to empty the container ist2=c×(h2-0)=c×h2...2t1t2=c×h(2-12)c×h2=(2-1)Regards 5 View Full Answer