The acceleration of the electron is a=eEm in the upward direction. The horizontal velocity remains v0 as there is no acceleration in this direction. Thus, the time taken in crossing the field is:
t=lv0
The upward component of the velocity of the electron as it emerges from the field region is:
vy=at=eElmv0
The horizontal component of the velocity remains vx=v0
The angle θ made by the resultant velocity with the original direction is given by:
tanθ=vyvx
Thus, the electron deviates by an angle:
θ=tan−1eElmv02