A women has 10 keys out of which only 1 opens the lock, she tries each key one by one keeping the failed ones aside, then what is the probability that the 7th key is the one which opens the lock? (p lz by tomorrow evening, on 

3/10
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Numbr r of failed keys=6 Left keys=4 Total keys=10 So the probability of 7th key to open the lock =4/10
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