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AB AND AC ARE TWO CHORDS OF CIRCLE OF RADIUS R.IF AB=2AC AND PERPENDICULAR IS DRAWN FROM THE CENTRE ON THESE CHORDS ARE OF LENGTH A AND B.PROVE THAT 4B2=A2+3R2.

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Ques wrng
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Check the question again
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I didn't understand ur question. Please check it again.
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it should be 4b2=a2+3r2
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please send pic
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please send only answer
 
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easy
 
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Please find this answer

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It's a correct question and very nice question.
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this is the answer

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the sol is correct?
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The question is correct.
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can you please send pic.
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https://youtu.be/NA-3UeamBOM please visit
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The question is nice and easy .....the answer is A2 + 3R2 =4B2
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Kindly find the solution below hopefully it will help you

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A2 + 3R2 =4B2 will be the final answer ...u can take the sum explanation from above most  answers
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4q^2 = p^2 + 3r^2. is answweer
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(*-*)
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