ABCD is a rectangle. BC : AC = 1 : root 2. AC is the diagonal and AE is the bisector of angle CAD, then the ratio of lengths of DE and AE is?

Dear student


Given: ABCD is  a  rectangleand BCAC=12ADE=90°  All the angles of a  rectangle are 90°Also,Opposite sides are equal in  a rectangleBC=AD=1 unit,Now consider ADEsin90°=ADAE1=ADAEAE=11=1 unitAgain in ADE,by pythagoras theoremAE2=AD2+DE212=12+DE2DE=0 which is not possible.So kindly recheck your question and provide the figure.
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Experts, help please! 
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Given, BC:AC = 1:root2 
BC(root2) = AC

Consider triangle ABC, right angled at B. Then,
AB2 + BC2 = AC2 
AB2 + BC2 = [BC(root2)]2
AB2 + BC2 = 2BC2 
AB2 = BC2
AB=BC

=> Since BC = AD and AB = DC (rectangle's sides)
=> AB = BC = CD = DA 

Let them be x cm.
Sorry, I can't figure out the rest. Experts, please help! 
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