Given, BC:AC = 1:root2
BC(root2) = AC
Consider triangle ABC, right angled at B. Then,
AB
2 + BC
2 = AC
2
AB
2 + BC
2 = [BC(root2)]
2
AB
2 + BC
2 = 2BC
2
AB
2 = BC
2
AB=BC
=> Since BC = AD and AB = DC (rectangle's sides)
=> AB = BC = CD = DA
Let them be x cm.
Sorry, I can't figure out the rest. Experts, please help!