Assume that 100 cc. of 0.1 M solution of H2SO4 is needed to neutralise 200 cc of Ba(OH)2 solution.The normality of Ba(OH)2 solution is: Share with your friends Share 4 Geetha answered this According to volumetric principleV1N1 = V2N2Volume of H2SO4 = 100 mlNormality of H2SO4 = 0.1 M= 0.1 × 2 = 0.2 NVolume of Ba(OH)2 = 250 mlNormality of Ba(OH)2 = N2Substitute100 × 0.2 = 250 × N2N2 = 100 × 0.2250 =0.08 N -24 View Full Answer