Calculate oxidation number - 1. of Ni in [Ni(CO)4]2+ 2. of Pt in K[PtCl3(NH3)]
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- Oxidation Number of Nickel (Ni):
Let the Oxidation Number of Ni be 'x'.
CO is a neutral ligand so its Oxidation number is 0.
Overall charge on the complex is +2.
Now,
x + 4(0) = +2
x = +2
So, Oxidation Number of Nickel in the complex is +2.
CO is a neutral ligand so its Oxidation number is 0.
Overall charge on the complex is +2.
Now,
x + 4(0) = +2
x = +2
So, Oxidation Number of Nickel in the complex is +2.
- Oxidation Number of Platinum (Pt):
Let the Oxidation Number of Pt be 'x'.
Cl is an Mono-anionic Ligand so, its Oxidation Number is -1.
NH3 is a Neutral Ligand so, O.N. is 0.
Overall charge on the complex is -1 (as Potassium cation is connected with it and its O.N. is +1).
Now,
x + 3(-1) + 0 = -1
x = +2
So, Oxidation Number of Platinum in the complex is +2.
Cl is an Mono-anionic Ligand so, its Oxidation Number is -1.
NH3 is a Neutral Ligand so, O.N. is 0.
Overall charge on the complex is -1 (as Potassium cation is connected with it and its O.N. is +1).
Now,
x + 3(-1) + 0 = -1
x = +2
So, Oxidation Number of Platinum in the complex is +2.
Hope this information clears your doubts about the topic
Keep asking!!
Regards