Calculate the value of angular momentum n=1

Dear student,

Your question is not complete. 
However, I have given the solution as per my understanding.

We are supposed to give the angular momentum for an electron in hydrogen-like atom for shell n = 1.
According to the principle of quantisation of angular momentum, the angular momentum of an electron orbiting in the n^th shell of an atom is an integral multiple of $\frac{h}{2\mathrm{\pi }}$., where h is Planck's constant.
The angular momentum is given by mv_nr_n , m is mass of e^- ,v_n is its velocity in n^th orbit and r_n is radius of n^th orbit.
 $\Rightarrow$ mv_nr_n  =  $n *\frac{h}{2\mathrm{\pi }}$
Here n =1, so angular momentum is $\frac{h}{2\mathrm{\pi }}$ =   $\frac{6.62 * {10}^{-34}}{2\mathrm{\pi }} = 1.054 * {10}^{-34 }kg m^2/s$

Hope it helps you !
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