Construct a triangle with length of base 5cm and angles of base 60 degree and 30 degree. Then construct a triangle whose sides are in the ratio of 7/3 to this triangle

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Solution:B=60° and C=30°Sum of all interior angles in a triangle is =180°A+B+C=180Putting value of B and C,A+60+30=180A+90=180A=180-90 A=90°Step 1: Draw a line segment BC=5cmStep 2: Draw an angle of 60° at point B and 30° at point C, Intersect at point A at 90°Step 3: Draw ray BX making an acute angle with BC on opposite side of vertex AStep 4: Locate 7 points on BXStep 5: Join B3C, Draw a line through B7 parallel to B3C intersecting extended BC at C'Step 6: Through C', draw a line parallel to AC intersecting extended line segment at A'A'BC' is the required triangle


NOTE: Angle drawn with the help of D

 
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