construct an isosceles triangle ABC, when base BC=6.2 cm and altitude=4.4 cm.
Dear Student,
![](https://s3mn.mnimgs.com/img/shared/ck-files/ck_56dd57665a356.png)
Steps of construction:
1. Draw a line segment BC = 6.2 cm.
2. Draw a perpendicular bisector XY of BC which intersects it at point D.
3. With D as centre and radius 4.4 cm, draw an arc to cut the ray DX at point A.
4. Join AB and AC.
Hence, ABC is the required triangle.
Hope this information will clear your doubts about the topic.
If you have any more doubts, just ask here on the forum and our expert will try to help you out as soon as possible.
Regards
![](https://s3mn.mnimgs.com/img/shared/ck-files/ck_56dd57665a356.png)
Steps of construction:
1. Draw a line segment BC = 6.2 cm.
2. Draw a perpendicular bisector XY of BC which intersects it at point D.
3. With D as centre and radius 4.4 cm, draw an arc to cut the ray DX at point A.
4. Join AB and AC.
Hence, ABC is the required triangle.
Hope this information will clear your doubts about the topic.
If you have any more doubts, just ask here on the forum and our expert will try to help you out as soon as possible.
Regards