Dear experts why is equation 2 given in your site, equation 1 only should be used. Because for all the questions they go by eq 1 method . They are talking something in terms of atomic mass nuclear mass. Why is that logic not applied for all qs? Why dont we ignore positron mass since q is about max k.e. of positron

Dear student,
 

The given nuclear reaction is:


m’ = Respective nuclear masses 
If atomic masses are used instead of nuclear masses, then we have to add 6 me in the case of 'Cand 5 me in the case of 'B.




Q=Ed+Ev+Ee

The daughter nucleus is too heavy compared to e+ and v , so it carries negligible energy.Ed =0, if the kinetic energy carried by the neutrino is minimum (zero), the positron carries maximum energy and this is equal to Q.

Regards

 

 

 
 

  • 0
This is the question

  • 0
What are you looking for?