Experts can i have the answer for the 26 th question after ' OR' ( part 4) Share with your friends Share 0 Hina Parveen answered this Dear Student, Q26 (iv) CH3-CH=CH2 (A)→Br2/CCl4 CH3-CH(Br)-CH2Br(B)→-2H2Oalc2 KOH CH3-C≡CH (C) +2KBr+H2O CH3-C≡CH (C) +Na →CH3-C≡C-Na CH3-C≡CH →Hg2+,H2SO4 CH3-(C=O) - CH3 (D) ketone Regards! 0 View Full Answer
