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 Find the components of vector A=2icap + 3j cap along the directions of vector i cap+j cap and i cap - j cap .

Given that

We know,

= component of a along b.

So, a cosθ = Component of a along b.

Component a along c is given by

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(1) a = 2i + 3j
b = i + j

(a.b)/|b|

Component= 5/√2 (Also called projection)

(2)

a = 2i + 3j
b = i - j

Component= (2-3)/

√2
Projection = -1/√2
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