find the principal that yield yield a compound interest of rupees 1632 in 2 years at 4% is rate of interest per annum

dear student,

we know that 
amount = principal + compound  interest
compound interest = amount - principal 
compound interest = 1632
Amount = P ( 1 + $\frac{r}{100}$)ⁿ   , where P = principal , time = n , r = rate of interest 
1632 = P(1+ $\frac{r}{100}$)ⁿ - P 
1632 = P( 1 + $\frac{4}{100}$)² - P 
1632 =  P( $\frac{26}{25}$)²- P
1632 = P[ $\frac{676}{625}$- 1]
1632 = P[ $\frac{676-625}{625}$]
1632 = P[$\frac{51}{625}$]
P = $\frac{1632\times 625}{51}$
P = 20000

Regards