Given that (k-6) is the highest common factor of 56 and 77 .Find the value of k?          Q6. John took some marbles. He made groups of five with them and found that one marble was left over.He tried making groups of six and groups of four. Each time one marble was left over. What is the smallest number of marbles that John had ?     

Dear Student,
Q-  Given that (k-6) is the highest common factor of 56 and 77 .Find the value of k?  
Solution- 
Prime Factorization of 56 = 2×2×2×7Prime Factorization of 77=7×11HCF of 56 and 77 = 7As per question, k-6 is equal to 7k-6=7k=7+6k=13For other question, we request you to please ask in separate thread.Regards

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