Hi mam,
This is Padma.
How to do this question?
when 110g of Mn dissolving in dil HNO3 at 27 C under atmospheric pressure, the work done is?
a)2494.2J
b)-2494.2J
c)-4988.4J
d)4988.4J
Dear student
No.of moles of Mn= wt of Mn/ molar mass
= 110g/55g/mol
= 2mol
T= 27oC= 300K
W= -nRT
= -2. 8.314. 300
= - 4988.4J
Hence option d is correct
Regards
No.of moles of Mn= wt of Mn/ molar mass
= 110g/55g/mol
= 2mol
T= 27oC= 300K
W= -nRT
= -2. 8.314. 300
= - 4988.4J
Hence option d is correct
Regards