How many different words can be formed of the letters 'MALENKOV' so that: 1. No two vowels are together 2. The vowels may occupy odd places Please give no links I'll need the answer with full method Share with your friends Share 0 Aarushi Mishra answered this 'MALENKOV'Let us separate vowels and consonants, There are 3 vowels namely A,E and O. There are 5 consonants namely M,L,N,K and V.Let us place first consonants and at remainig place we will place vowels___ X ___ X ___ X ___ X ___ X ___X represents positions of consonants. In between consonats we will place vowels.No. of ways of arranging consonants=P55=5!5-5!=5!0!=5!There are 6 possible ways of placing vowels and we have onky three vowels. Choose three places by C36 and then we can arrange three vowels in 3! waysTotal number of ways of placing vowels=C36×3!Total number of words that can be formed from given word, with no vowels together=C36×3!×5!=6!3! 3!×3!×5!=20×6!=20×70=1440There are total 8 letters with us___ ___ ___ ___ ___ ___ ___ ___ 1 2 3 4 5 6 7 8The vowels need to occupy odd placesTotal number of odd places are 4We choose 3 places using C34 and then the 3 vowels can be arranged in those three places in 3! waysTotal number of ways of placing vowels= C34×3!Consonants can be placed in remaining 5 places in 5! waysTotal number of ways of placing consonants= 5!Total number of words with vowels at odd places=5!×C34×3!=120×4×6=2880 -1 View Full Answer Deepika answered this Please find this answer -1 Deepika answered this Please find this answer 0
