how to construct an equilateral triangle whose each side is 8cm?
draw a line of 8cm. let it be BC.
open the compass till a length of 8 cm.
with B as center cut an arc on the top.
with C as center and same radius 8 cm cut an arc intersecting the previous one.
the point of intersection will be vertex A.
join AB and AC.
∆ABC is the required triangle
open the compass till a length of 8 cm.
with B as center cut an arc on the top.
with C as center and same radius 8 cm cut an arc intersecting the previous one.
the point of intersection will be vertex A.
join AB and AC.
∆ABC is the required triangle