If 3 l of nh3 reacts with 1.2 l of HCl then volume of gaseous mix after reaction Nh3 + HCl ---> nh4cl

Dear Reaction is NH3 + HCl----> NH4Cl, mole directly proportional to lit so 1 mole or lit of each NH3 & HCl react to produce NH4Cl, now 1.2 L is HCl is limiting so NH3 will left and NH4Cl is solid so its volume will not be considered

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