If sec(5A) = cosec(A-30) where 5A & (A-30) are acute angles , find the value of tan 3A.

90-5A=A-30; 6A=120 ; A= 20
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Now tan 3A= tan( 3?20)= tan 60= root 3
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Thankyou :)
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A=20.tan 3A~tan60=?3
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Hope you understandd

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sec(5A) = cosec (A-30)
=> cosec (90-5A) = cosec (A-30)
Since they are acute angles,
Therefore,
         90-5A = A- 30
       => 6A=120
       => A=20 degrees

          
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