In a LCR circuit, = 5 H, c = 80mew F and R= 40 ohms connected to 240V source. Calculate frequency, current and potential drop across the capacitor at resonance. Share with your friends Share 0 Shobhit Mittal answered this Dear Student, L=5 H , C=80*10-6 FR=40 ohm ,V =240vresonant frequency f=12π1LC=12π15*80*10-6=12π100004=1004π HzI=240R=24040=60Apotential drop =I1ωc=60*150*80*10-6=10000040=2500 v across the capacitor.Regards 1 View Full Answer