In ΔABC, D is a point on the side BC such that AB = AD = DC. If ∠BAD = 28°, find ∠BAC.

Dear Student,

In ABDLet ABD=ADB =x   AB=ADandBAD+ABD+ADB=180°        Sum of all the angles of triangle is 180°28°+x+x=180°2x=180°-28°x=1522x=76°Hence ABB=ADB=76°Now, DAC is angle opposite to side DC and DC=AD=ABHence, DAC=ABD=ADB=76°Now, BAC=BAD+DAC                        =76°+28°                        =104°
Regards

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