In the given figure, if AB||DE, ∠BPQ = (5x-20)0 and ∠PQD=(2x-10)0 , find the value of y andz


 

Dear student
Since AB is a straight line.Therefore, APQ+BPQ=180°     Linear pairAPQ+5x-20°=180°APQ+5x=200°     ...(1)Also,APQ=PQD    Alternate interior angleAPQ=2x-10°Substitute this value in eq(1), we get2x-10°+5x=200°7x=210°x=30°AndBPQ=5x-20°=150°-20°=130°and PQD=2x-10°=60°-10°=50°Here y and z are not labelled in the figure.
Regards

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