In the given figure PQRS is a rhombus such that RQ is produced to E and SE is joined - Maths -

Question

In the given figure PQRS is a rhombus such that RQ is produced
to E and SE is joined SE and PR intersect at D Prove that SD RE
=
SR DE
the algebraic sum of the deviations of a frequency distribution
from its mean is always +ve or -ve??

Anuradha Sharma · Accepted Answer

The figure can be given as,
<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/images/trtrtr%20png"
style="width: 193px; height: 158px;">
In the triangle PDS and RDE, ∠PDS=∠RDE Vertically opposite angle∠PSD=∠RED corresponding interior angle as PS|| RE and SE transversal line ∠SPD=∠DRE  corresponding interior angleSo △PDS ~△RDESDDE=PSRE=SRREAs PQRS is a rhomus so PS=SRSo, SD×RE=SR×DEHence  Proved

2) The algebraic sum of the deviations of a frequency distribution
from its mean is zero

In the given figure PQRS is a rhombus such that RQ is produced to E and SE is joined. SE and PR intersect at D. Prove that SD . RE =SR . DE. the algebraic sum of the deviations of a frequency distribution from its mean is.. always +ve or -ve??

In the given figure PQRS is a rhombus such that RQ is produced to E and SE is joined. SE and PR intersect at D. Prove that SD . RE =
SR . DE.

the algebraic sum of the deviations of a frequency distribution from its mean is.. always +ve or -ve??