Inside a 9cm radius circle an isosceles triangle ABC exists with side AB = 6cm and AB = AC . Find the area of triangle .
Let AP = x cm
In quadrilateral OBAC,
OB = OC = 9 cm ( Radius of the circle )
And, AB = AC = 6 cm ( Given )
Thus, OBAC forms a kite and we know that, the diagonals of a kite are perpendicular to each other.
Therefore,
And,
Substitute value of x in equation (1), we get,
Therefore,
Hence, area of triangle is .