NO LINKS PLZ. ANSWER IN LINKS WAS NOT SATISFYING. (answer 2 root 2 u)
Let escape velocity of a body kept at surface of a planet is u. if it is projected at a speed of 200% more than escape speed , then its speed in interstellar space will be
Dear Student ,
If a body is projected with speed Vi = KVe (k>1), the final interstellar speed is (√k²-1)Ve
if Vi = KVe (k<1) directed vertically upward the maximum height from centre of earth of radius R attained by the body is r = R /(1-K²)
and hence its maximum height from surface of earth is H= r-R = (R /1-K²) - R
= RK²/(1-K²)
By this method now velocity is V+2 V = 3 V
So k=3
Finally interstellar speed = (√k²-1) = √8 = 2√2
Regards
If a body is projected with speed Vi = KVe (k>1), the final interstellar speed is (√k²-1)Ve
if Vi = KVe (k<1) directed vertically upward the maximum height from centre of earth of radius R attained by the body is r = R /(1-K²)
and hence its maximum height from surface of earth is H= r-R = (R /1-K²) - R
= RK²/(1-K²)
By this method now velocity is V+2 V = 3 V
So k=3
Finally interstellar speed = (√k²-1) = √8 = 2√2
Regards