PbS + H2O2 = PbSO4 + H2O Balance completely by oxidation number method - Chemistry - Redox Reactions

Question

PbS + H2O2 =>PbSO4 +
H2O
Balance completely by oxidation number method

Geetha · Accepted Answer

The oxidation number of Pb does not change in both sidesThe oxidation number of S in LHS = -2The oxidation number of S in RHS  +2+x+4(-2)=0             x=+6Thus in the oxidation number change in S is 8
 The oxidation number of oxygen in LHS = -1The oxidation number of oxygen in RHS = -2Thus in the oxidation number change in O is 1
PbS + H2O2 → PbSO4 + H2O 8             2(1)Cross multiply,PbS + H2O2 → PbSO4 + H2O 8             2(1)2PbS +8 H2O2 → PbSO4 + H2O Thus balance the Lead and hydrogen in RHS2 PbS +8 H2O2 → 2 PbSO4 + 8 H2OPbS +4 H2O2 → PbSO4 + 4 H2O

PbS + H2O2 =>PbSO4 + H2O Balance completely by oxidation number method

PbS + H₂O₂ =>PbSO₄+ H₂O
Balance completely by oxidation number method